w^2-6w-36=75

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Solution for w^2-6w-36=75 equation:



w^2-6w-36=75
We move all terms to the left:
w^2-6w-36-(75)=0
We add all the numbers together, and all the variables
w^2-6w-111=0
a = 1; b = -6; c = -111;
Δ = b2-4ac
Δ = -62-4·1·(-111)
Δ = 480
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{480}=\sqrt{16*30}=\sqrt{16}*\sqrt{30}=4\sqrt{30}$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-4\sqrt{30}}{2*1}=\frac{6-4\sqrt{30}}{2} $
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+4\sqrt{30}}{2*1}=\frac{6+4\sqrt{30}}{2} $

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